3.717 \(\int \frac {x^2 \sqrt {\tan ^{-1}(a x)}}{(c+a^2 c x^2)^3} \, dx\)

Optimal. Leaf size=83 \[ \frac {\sqrt {\frac {\pi }{2}} S\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\tan ^{-1}(a x)}\right )}{64 a^3 c^3}+\frac {\tan ^{-1}(a x)^{3/2}}{12 a^3 c^3}-\frac {\sqrt {\tan ^{-1}(a x)} \sin \left (4 \tan ^{-1}(a x)\right )}{32 a^3 c^3} \]

[Out]

1/12*arctan(a*x)^(3/2)/a^3/c^3+1/128*FresnelS(2*2^(1/2)/Pi^(1/2)*arctan(a*x)^(1/2))*2^(1/2)*Pi^(1/2)/a^3/c^3-1
/32*sin(4*arctan(a*x))*arctan(a*x)^(1/2)/a^3/c^3

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Rubi [A]  time = 0.14, antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {4970, 4406, 3296, 3305, 3351} \[ \frac {\sqrt {\frac {\pi }{2}} S\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\tan ^{-1}(a x)}\right )}{64 a^3 c^3}+\frac {\tan ^{-1}(a x)^{3/2}}{12 a^3 c^3}-\frac {\sqrt {\tan ^{-1}(a x)} \sin \left (4 \tan ^{-1}(a x)\right )}{32 a^3 c^3} \]

Antiderivative was successfully verified.

[In]

Int[(x^2*Sqrt[ArcTan[a*x]])/(c + a^2*c*x^2)^3,x]

[Out]

ArcTan[a*x]^(3/2)/(12*a^3*c^3) + (Sqrt[Pi/2]*FresnelS[2*Sqrt[2/Pi]*Sqrt[ArcTan[a*x]]])/(64*a^3*c^3) - (Sqrt[Ar
cTan[a*x]]*Sin[4*ArcTan[a*x]])/(32*a^3*c^3)

Rule 3296

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> -Simp[((c + d*x)^m*Cos[e + f*x])/f, x] +
Dist[(d*m)/f, Int[(c + d*x)^(m - 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rule 3305

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Sin[(f*x^2)/d], x], x,
Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 4406

Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[E
xpandTrigReduce[(c + d*x)^m, Sin[a + b*x]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0]
&& IGtQ[p, 0]

Rule 4970

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(q_), x_Symbol] :> Dist[d^q/c^(m
+ 1), Subst[Int[((a + b*x)^p*Sin[x]^m)/Cos[x]^(m + 2*(q + 1)), x], x, ArcTan[c*x]], x] /; FreeQ[{a, b, c, d,
e, p}, x] && EqQ[e, c^2*d] && IGtQ[m, 0] && ILtQ[m + 2*q + 1, 0] && (IntegerQ[q] || GtQ[d, 0])

Rubi steps

\begin {align*} \int \frac {x^2 \sqrt {\tan ^{-1}(a x)}}{\left (c+a^2 c x^2\right )^3} \, dx &=\frac {\operatorname {Subst}\left (\int \sqrt {x} \cos ^2(x) \sin ^2(x) \, dx,x,\tan ^{-1}(a x)\right )}{a^3 c^3}\\ &=\frac {\operatorname {Subst}\left (\int \left (\frac {\sqrt {x}}{8}-\frac {1}{8} \sqrt {x} \cos (4 x)\right ) \, dx,x,\tan ^{-1}(a x)\right )}{a^3 c^3}\\ &=\frac {\tan ^{-1}(a x)^{3/2}}{12 a^3 c^3}-\frac {\operatorname {Subst}\left (\int \sqrt {x} \cos (4 x) \, dx,x,\tan ^{-1}(a x)\right )}{8 a^3 c^3}\\ &=\frac {\tan ^{-1}(a x)^{3/2}}{12 a^3 c^3}-\frac {\sqrt {\tan ^{-1}(a x)} \sin \left (4 \tan ^{-1}(a x)\right )}{32 a^3 c^3}+\frac {\operatorname {Subst}\left (\int \frac {\sin (4 x)}{\sqrt {x}} \, dx,x,\tan ^{-1}(a x)\right )}{64 a^3 c^3}\\ &=\frac {\tan ^{-1}(a x)^{3/2}}{12 a^3 c^3}-\frac {\sqrt {\tan ^{-1}(a x)} \sin \left (4 \tan ^{-1}(a x)\right )}{32 a^3 c^3}+\frac {\operatorname {Subst}\left (\int \sin \left (4 x^2\right ) \, dx,x,\sqrt {\tan ^{-1}(a x)}\right )}{32 a^3 c^3}\\ &=\frac {\tan ^{-1}(a x)^{3/2}}{12 a^3 c^3}+\frac {\sqrt {\frac {\pi }{2}} S\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\tan ^{-1}(a x)}\right )}{64 a^3 c^3}-\frac {\sqrt {\tan ^{-1}(a x)} \sin \left (4 \tan ^{-1}(a x)\right )}{32 a^3 c^3}\\ \end {align*}

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Mathematica [C]  time = 0.42, size = 141, normalized size = 1.70 \[ \frac {32 \tan ^{-1}(a x) \left (3 a x \left (a^2 x^2-1\right )+2 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)\right )-3 \left (a^2 x^2+1\right )^2 \sqrt {-i \tan ^{-1}(a x)} \Gamma \left (\frac {1}{2},-4 i \tan ^{-1}(a x)\right )-3 \left (a^2 x^2+1\right )^2 \sqrt {i \tan ^{-1}(a x)} \Gamma \left (\frac {1}{2},4 i \tan ^{-1}(a x)\right )}{768 a^3 c^3 \left (a^2 x^2+1\right )^2 \sqrt {\tan ^{-1}(a x)}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(x^2*Sqrt[ArcTan[a*x]])/(c + a^2*c*x^2)^3,x]

[Out]

(32*ArcTan[a*x]*(3*a*x*(-1 + a^2*x^2) + 2*(1 + a^2*x^2)^2*ArcTan[a*x]) - 3*(1 + a^2*x^2)^2*Sqrt[(-I)*ArcTan[a*
x]]*Gamma[1/2, (-4*I)*ArcTan[a*x]] - 3*(1 + a^2*x^2)^2*Sqrt[I*ArcTan[a*x]]*Gamma[1/2, (4*I)*ArcTan[a*x]])/(768
*a^3*c^3*(1 + a^2*x^2)^2*Sqrt[ArcTan[a*x]])

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*arctan(a*x)^(1/2)/(a^2*c*x^2+c)^3,x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*arctan(a*x)^(1/2)/(a^2*c*x^2+c)^3,x, algorithm="giac")

[Out]

sage0*x

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maple [A]  time = 0.63, size = 66, normalized size = 0.80 \[ \frac {3 \sqrt {2}\, \sqrt {\pi }\, \sqrt {\arctan \left (a x \right )}\, \mathrm {S}\left (\frac {2 \sqrt {2}\, \sqrt {\arctan \left (a x \right )}}{\sqrt {\pi }}\right )+32 \arctan \left (a x \right )^{2}-12 \sin \left (4 \arctan \left (a x \right )\right ) \arctan \left (a x \right )}{384 a^{3} c^{3} \sqrt {\arctan \left (a x \right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*arctan(a*x)^(1/2)/(a^2*c*x^2+c)^3,x)

[Out]

1/384/a^3/c^3*(3*2^(1/2)*Pi^(1/2)*arctan(a*x)^(1/2)*FresnelS(2*2^(1/2)/Pi^(1/2)*arctan(a*x)^(1/2))+32*arctan(a
*x)^2-12*sin(4*arctan(a*x))*arctan(a*x))/arctan(a*x)^(1/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*arctan(a*x)^(1/2)/(a^2*c*x^2+c)^3,x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: expt: undefined: 0 to a negative e
xponent.

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^2\,\sqrt {\mathrm {atan}\left (a\,x\right )}}{{\left (c\,a^2\,x^2+c\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^2*atan(a*x)^(1/2))/(c + a^2*c*x^2)^3,x)

[Out]

int((x^2*atan(a*x)^(1/2))/(c + a^2*c*x^2)^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {x^{2} \sqrt {\operatorname {atan}{\left (a x \right )}}}{a^{6} x^{6} + 3 a^{4} x^{4} + 3 a^{2} x^{2} + 1}\, dx}{c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*atan(a*x)**(1/2)/(a**2*c*x**2+c)**3,x)

[Out]

Integral(x**2*sqrt(atan(a*x))/(a**6*x**6 + 3*a**4*x**4 + 3*a**2*x**2 + 1), x)/c**3

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